Count Number of Trailing Zeros in Factorial C Program

By | March 22, 2016

C Program To Count Number of Trailing Zeroes in Factorial of Number

Here’s a C Program To Count the Number of Trailing Zeros in Factorial of a Number. While Calculating Factorial of an Integer, you may get a Long Number ending with Multiple Zeroes. This Code Finds the Total Number of Zeroes at the End of a Factorial of any Number.

Example For Trailing Zeros in Factorial of Number

5! = 120
Number of Trailing Zeros = 1


50! = 30414093201713378043612608166064768844377641568960512000000000000

It is also expressed as 3.0414093201713E+64

Here, we have to consider Prime Factors of the Number of which the Factorial is being calculated. Remember, Trailing Zeros are always generated if the Number is a Prime Factor of 5 and 2.

Also Read: C Program To Find Prime Numbers


Method 1: C Program To Find Number of Trailing Zeros in Factorial of a Number using While Loop


Also Read: C Program To Calculate Factorial of a Number using Loops

Method 2: C Program To Count Number of Trailing Zeros in Factorial of an Integer using For Loop

Also Read: Calculate Factorial of Number using Recursion in C Programming

Output

C Program To Count Number of Trailing Zeros in Factorial of a Number

If you have any doubts or compilation errors in this Code to Count Number of Trailing Zeros in a Factorial of any Integer, let us know about it in the Comment Section below.

4 thoughts on “Count Number of Trailing Zeros in Factorial C Program

  1. Dipak Kale

    Can we find zeros at the end of a float number that has decimal points in it?

    Reply
    1. Vijay Kumar Sawant

      I think it is possible! You need to take in float values!

      Reply
  2. sinto das kollan

    brother ,input 3
    enter 6,count _zero 1
    enter 15 count _zero 3
    but when i print sum of count

    Reply

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