C Program To Count Number of Trailing Zeroes in Factorial of Number
Here’s a C Program To Count the Number of Trailing Zeros in Factorial of a Number. While Calculating Factorial of an Integer, you may get a Long Number ending with Multiple Zeroes. This Code Finds the Total Number of Zeroes at the End of a Factorial of any Number.
Example For Trailing Zeros in Factorial of Number
5! = 120
Number of Trailing Zeros = 1
50! = 30414093201713378043612608166064768844377641568960512000000000000
It is also expressed as 3.0414093201713E+64
Here, we have to consider Prime Factors of the Number of which the Factorial is being calculated. Remember, Trailing Zeros are always generated if the Number is a Prime Factor of 5 and 2.
Also Read: C Program To Find Prime Numbers
Method 1: C Program To Find Number of Trailing Zeros in Factorial of a Number using While Loop
Method 2: C Program To Count Number of Trailing Zeros in Factorial of an Integer using For Loop
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