Pattern Program in C Language

By | June 16, 2016
 

List of Pattern Program in C Programming Language

Learn How To Print Pattern Program in C Programming Language. It is important that you should understand How A For Loop Works in C Programming before going further with this C Program To Generate Patterns of Numbers.

Note: This Java Program to Print Pattern Programs is edited with gEdit Editor and executed using Terminal in Linux Ubuntu Operating System.


Pattern 1: C Program To Print Pattern of Numbers using While Loop

1 2 3 4 5
5 4 3 2
2 3 4
4 3
3

Output

Print Pattern Program in C

Pattern 2: C Program To Print Characters in Pattern using For Loop

ABCDDBCA
ABC      CBA
AB            BA
A                 A

 

Output

Code To Develop Pattern Programs in C

If you have any compilation error or doubts in this Code For Printing Pattern Program in C Programming, let us know about in the comment section below.

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8 thoughts on “Pattern Program in C Language

  1. Suresh Pandule

    kaise to kiya he just check it

    static void Main(string[] args)
    {
    int row,count,refcount=1,count1,refcount1=4,count2,refcount2=3,count3,refcount3=2;
    Console.Write(“Enter the No of Rows You Want”);
    row = Int32.Parse(Console.ReadLine());

    for (int i = 1; i <= row; i++)
    {
    count3 = refcount3;
    count2 = refcount2;
    count1=refcount1;
    count=refcount;

    if (i <= 3)
    {
    for (int j = 1; j 0)
    {
    Console.Write(“*”);
    }
    else if (count1– > 0)
    {
    Console.Write(“#”);
    }
    }
    else
    {
    if (count1– > 0)
    {
    Console.Write(“#”);
    }
    else if (count– > 0)
    {
    Console.Write(“*”);
    }
    }

    }
    Console.WriteLine();
    ++refcount;
    –refcount1;
    }
    else
    {
    for (int j = 1; j 0)
    {
    Console.Write(“#”);
    }
    else if (count3– > 0)
    {
    Console.Write(“*”);
    }
    }
    else
    {
    if (count3– > 0)
    {
    Console.Write(“*”);
    }
    else if (count2– > 0)
    {
    Console.Write(“#”);
    }
    }

    }
    Console.WriteLine();
    ++refcount2;
    –refcount3;
    }

    } Console.ReadKey();
    }

    Reply
  2. Suresh Pandule

    kaise to kiya he maine

    static void Main(string[] args)
    {
    int row,count,refcount=1,count1,refcount1=4,count2,refcount2=3,count3,refcount3=2;
    Console.Write(“Enter the No of Rows You Want”);
    row = Int32.Parse(Console.ReadLine());

    for (int i = 1; i <= row; i++)
    {
    count3 = refcount3;
    count2 = refcount2;
    count1=refcount1;
    count=refcount;

    if (i <= 3)
    {
    for (int j = 1; j 0)
    {
    Console.Write(“*”);
    }
    else if (count1– > 0)
    {
    Console.Write(“#”);
    }
    }
    else
    {
    if (count1– > 0)
    {
    Console.Write(“#”);
    }
    else if (count– > 0)
    {
    Console.Write(“*”);
    }
    }

    }
    Console.WriteLine();
    ++refcount;
    –refcount1;
    }
    else
    {
    for (int j = 1; j 0)
    {
    Console.Write(“#”);
    }
    else if (count3– > 0)
    {
    Console.Write(“*”);
    }
    }
    else
    {
    if (count3– > 0)
    {
    Console.Write(“*”);
    }
    else if (count2– > 0)
    {
    Console.Write(“#”);
    }
    }

    }
    Console.WriteLine();
    ++refcount2;
    –refcount3;
    }

    } Console.ReadKey();
    }

    Reply
  3. Suresh Pandule

    Output:-

    &#######
    #######&&
    &&&######
    #####&&&&
    &&&&&####
    #####&&&&
    &&&######
    #######&&
    &#######

    class Program
    {
    static void Main(string[] args)
    {
    int center_row, row,count,refcount=1,count1,refcount1,count2,refcount2,count3,refcount3;

    Console.Write(“Enter the No of Rows You Want”);
    row = Int32.Parse(Console.ReadLine());
    center_row = (row / 2) + 1;
    refcount1 = row – 1;
    refcount2 = center_row;
    refcount3 = row / 2;
    for (int i = 1; i <= row; i++)
    {
    count3 = refcount3;
    count2 = refcount2;
    count1=refcount1;
    count=refcount;

    if (i <= center_row)
    {
    for (int j = 1; j 0)
    {
    Console.Write(“&”);
    }
    else if (count1– > 0)
    {
    Console.Write(“#”);
    }
    }
    else
    {
    if (count1– > 0)
    {
    Console.Write(“#”);
    }
    else if (count– > 0)
    {
    Console.Write(“&”);
    }
    }

    }
    Console.WriteLine();
    ++refcount;
    –refcount1;
    }
    else
    {
    for (int j = 1; j 0)
    {
    Console.Write(“#”);
    }
    else if (count3– > 0)
    {
    Console.Write(“&”);
    }
    }
    else
    {
    if (count3– > 0)
    {
    Console.Write(“&”);
    }
    else if (count2– > 0)
    {
    Console.Write(“#”);
    }
    }

    }
    Console.WriteLine();
    ++refcount2;
    –refcount3;
    }

    } Console.ReadKey();
    }

    }

    Reply

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