Learn How To Find and Count Vowels in String in C Programming Language. The Number of Vowels in a String can be count using If Else, Switch Case and Pointers as well.
What is Vowel?
A letter representing a vowel sound, such as a, e, i, o, u.
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C Program To Count Vowels in String using If Else
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | #include<stdio.h> #include<string.h> int main() { int count = 0, i, length; char ch, str[30]; printf("\nEnter A String:\t"); scanf("%[^\n]s", str); for(i = 0; i < strlen(str); i++) { if(str[i] == 'a' || str[i] == 'e' || str[i] == 'i' || str[i] == 'o' || str[i] == 'u' || str[i] == 'A' || str[i] == 'E' || str[i] == 'I' || str[i] == 'O' || str[i] == 'U') { count++; } } printf("\nTotal Number of Vowels:\t%d\n", count); return 0; } |
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C Program To Count Number of Vowels in a String using Switch Case
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 | #include<stdio.h> #include<string.h> int main() { int count, sum = 0, length; char ch, str[30]; int a = 0, e = 0, i = 0, o = 0, u = 0, A = 0, E = 0, I = 0, O = 0, U = 0; printf("\nEnter A String:\t"); scanf("%[^\n]s", str); length = strlen(str); for(count = 0; count < length; count++) { ch = str[count]; switch(ch) { case 'a': a++; sum++; break; case 'e': e++; sum++; break; case 'i': i++; sum++; break; case 'o': o++; sum++; break; case 'u': u++; sum++; break; case 'A': A++; sum++; break; case 'E': E++; sum++; break; case 'I': I++; sum++; break; case 'O': O++; sum++; break; case 'U': U++; sum++; break; } } printf("\nTotal Number of Vowels:\t%d\n", sum); printf("\nCount of Vowel: a = %d", a); printf("\nCount of Vowel: e = %d", e); printf("\nCount of Vowel: i = %d", i); printf("\nCount of Vowel: o = %d", o); printf("\nCount of Vowel: u = %d", u); printf("\nCount of Vowel: A = %d", A); printf("\nCount of Vowel: E = %d", E); printf("\nCount of Vowel: I = %d", I); printf("\nCount of Vowel: O = %d", O); printf("\nCount of Vowel: U = %d\n", U); return 0; } |
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C Program To Count Vowels in String using Pointers
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 | #include<stdio.h> #include<string.h> int main() { int i, sum = 0; char str[30], *ptr; printf("\nEnter A String:\t"); scanf("%[^\n]s", str); ptr = str; while(*ptr != '\0') { if(*ptr == 'a' || *ptr == 'e' || *ptr == 'i' || *ptr == 'o' || *ptr == 'u' || *ptr == 'A' || *ptr == 'E' || *ptr == 'I' || *ptr == 'O' || *ptr == 'U') { sum++; } ptr++; } printf("\nTotal Number of Vowels:\t%d\n", sum); return 0; } |
Output
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